MOD 8 Synchronous Counter using T Flip-flop
This post is about how to design a MOD-8 Synchronous Counter using T Flip-flop step by step.
MOD 8 Synchronous Counter using T Flip-flop
Step 1: Find the number of Flip-flops needed
The number of Flip-flops required can be determined by using the following equation:
M ≤ 2N
where, M is the MOD number and N is the number of required flip-flops.
Here, MOD number is equal to 8. i.e., M = 8
Therefore, 8 ≤ 2N
=> N = 3
Therefore, to design a MOD 8 Counter, 3 flip-flops would be required.
Step 2: Write the excitation table of the flip-flop
Excitation table of T flip-flop is:
QN |
QN+1 |
T |
0 |
0 |
0 |
0 |
1 |
1 |
1 |
0 |
1 |
1 |
1 |
0 |
Step 3: Write the circuit state table by using excitation table
Circuit state table for designing MOD 8 Synchronous Counter using T Flip-flop would be
QA |
QB |
QC |
QA+1 |
QB+1 |
QC+1 |
TA
|
TB |
TC |
0 |
0 |
0 |
0 |
0 |
1 |
0 |
0 |
1 |
0 |
0 |
1 |
0 |
1 |
0 |
0 |
1 |
1 |
0 |
1 |
0 |
0 |
1 |
1 |
0 |
0 |
1 |
0 |
1 |
1 |
1 |
0 |
0 |
1 |
1 |
1 |
1 |
0 |
0 |
1 |
0 |
1 |
0 |
0 |
1 |
1 |
0 |
1 |
1 |
1 |
0 |
0 |
1 |
1 |
1 |
1 |
0 |
1 |
1 |
1 |
0 |
0 |
1 |
1 |
1 |
1 |
0 |
0 |
0 |
1 |
1 |
1 |
Step 4: Prepare K Map for each flip-flop input in terms of flip-flop outputs as the input variables
In this case inputs of the flip-flops are: TA, TB & TC
K Map for TA :
Therefore, TC = 1
Step 5: Draw the circuit using flip-flops and other gates correspond to the minimized expressions
Circuit for MOD 8 Synchronous Counter using T Flip-flop would be
In this way "MOD 8 Synchronous Counter using T Flip-flop" can be designed.
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